6b^2=16+20b

Solution for 6b^2=16+20b equation:

6b^2=16+20b

We move all terms to the left:

6b^2-(16+20b)=0

We add all the numbers together, and all the variables

6b^2-(20b+16)=0

We get rid of parentheses

6b^2-20b-16=0

a = 6; b = -20; c = -16;
Δ = b2-4ac
Δ = -202-4·6·(-16)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-28}{2*6}=\frac{-8}{12}
=-2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+28}{2*6}=\frac{48}{12}
=4
$